What is the solution for y^{''}+10y^'+16=10 ?

The solution for y^{''}+10y^'+16=10 is y=c_{1}+c_{2}e^{-10t}-(3t)/5

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y^{''}+10y^'+16=10

y^{^{''}} + 10 y^{^{'}} + 16 = 10

y = c_{1} + c_{2} e^{- 10 t} - \frac{3 t}{5}

Solution steps

y^{''} (t) + 10 y^{'} (t) + 16 = 10

Solve linear ODE:

y = c_{1} + c_{2} e^{- 10 t} - \frac{3 t}{5}

y = c_{1} + c_{2} e^{- 10 t} - \frac{3 t}{5}

What is the solution for y^{''}+10y^'+16=10 ?
The solution for y^{''}+10y^'+16=10 is y=c_{1}+c_{2}e^{-10t}-(3t)/5