What is the solution for y^{''}+y^'=cos(2x) ?

The solution for y^{''}+y^'=cos(2x) is y=c_{1}+c_{2}e^{-x}+1/10 sin(2x)-1/5 cos(2x)

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y^{''}+y^'=cos(2x)

y^{^{''}} + y^{^{'}} = cos (2 x)

y = c_{1} + c_{2} e^{- x} + \frac{1}{10} sin (2 x) - \frac{1}{5} cos (2 x)

Solution steps

y^{''} (x) + y^{'} (x) = cos (2 x)

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + \frac{1}{10} sin (2 x) - \frac{1}{5} cos (2 x)

y = c_{1} + c_{2} e^{- x} + \frac{1}{10} sin (2 x) - \frac{1}{5} cos (2 x)

What is the solution for y^{''}+y^'=cos(2x) ?
The solution for y^{''}+y^'=cos(2x) is y=c_{1}+c_{2}e^{-x}+1/10 sin(2x)-1/5 cos(2x)