What is the solution for y^{''}+y=4x^2 ?

The solution for y^{''}+y=4x^2 is y=c_{1}cos(x)+c_{2}sin(x)+4x^2-8

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y^{''}+y=4x^2

y^{^{''}} + y = 4 x^{2}

y = c_{1} cos (x) + c_{2} sin (x) + 4 x^{2} - 8

Solution steps

y^{''} (x) + y = 4 x^{2}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + 4 x^{2} - 8

y = c_{1} cos (x) + c_{2} sin (x) + 4 x^{2} - 8

What is the solution for y^{''}+y=4x^2 ?
The solution for y^{''}+y=4x^2 is y=c_{1}cos(x)+c_{2}sin(x)+4x^2-8