What is the solution for y^{''}-y^'-2y=3x+3 ?

The solution for y^{''}-y^'-2y=3x+3 is y=c_{1}e^{2x}+c_{2}e^{-x}-(3x)/2-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-y^'-2y=3x+3

y^{^{''}} - y^{^{'}} - 2 y = 3 x + 3

y = c_{1} e^{2 x} + c_{2} e^{- x} - \frac{3 x}{2} - \frac{3}{4}

Solution steps

y^{''} (x) - y^{'} (x) - 2 y = 3 x + 3

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- x} - \frac{3 x}{2} - \frac{3}{4}

y = c_{1} e^{2 x} + c_{2} e^{- x} - \frac{3 x}{2} - \frac{3}{4}

What is the solution for y^{''}-y^'-2y=3x+3 ?
The solution for y^{''}-y^'-2y=3x+3 is y=c_{1}e^{2x}+c_{2}e^{-x}-(3x)/2-3/4