What is the solution for (d^2-2d+1)y=xe^xsin(x) ?

The solution for (d^2-2d+1)y=xe^xsin(x) is y=c_{1}e^x+c_{2}xe^x-e^xxsin(x)-2e^xcos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(d^2-2d+1)y=xe^xsin(x)

(d^{2} - 2 d + 1) y = x e^{x} sin (x)

y = c_{1} e^{x} + c_{2} x e^{x} - e^{x} x sin (x) - 2 e^{x} cos (x)

Solution steps

(d^{2} - 2 d + 1) y = x e^{x} sin (x)

Solve linear ODE:

y = c_{1} e^{x} + c_{2} x e^{x} - e^{x} x sin (x) - 2 e^{x} cos (x)

y = c_{1} e^{x} + c_{2} x e^{x} - e^{x} x sin (x) - 2 e^{x} cos (x)

What is the solution for (d^2-2d+1)y=xe^xsin(x) ?
The solution for (d^2-2d+1)y=xe^xsin(x) is y=c_{1}e^x+c_{2}xe^x-e^xxsin(x)-2e^xcos(x)