What is the solution for y^{''}-4y^'+3y=5e^{3t} ?

The solution for y^{''}-4y^'+3y=5e^{3t} is y=c_{1}e^{3t}+c_{2}e^t+(5e^{3t}t)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-4y^'+3y=5e^{3t}

y^{^{''}} - 4 y^{^{'}} + 3 y = 5 e^{3 t}

y = c_{1} e^{3 t} + c_{2} e^{t} + \frac{5 e ^{3 t} t}{2}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 3 y = 5 e^{3 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{t} + \frac{5 e ^{3 t} t}{2}

y = c_{1} e^{3 t} + c_{2} e^{t} + \frac{5 e ^{3 t} t}{2}

What is the solution for y^{''}-4y^'+3y=5e^{3t} ?
The solution for y^{''}-4y^'+3y=5e^{3t} is y=c_{1}e^{3t}+c_{2}e^t+(5e^{3t}t)/2