What is the solution for 3y^{''}+8y^'-3y=8-3t ?

The solution for 3y^{''}+8y^'-3y=8-3t is y=c_{1}e^{t/3}+c_{2}e^{-3t}+t

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3y^{''}+8y^'-3y=8-3t

3 y^{^{''}} + 8 y^{^{'}} - 3 y = 8 - 3 t

y = c_{1} e^{\frac{t}{3}} + c_{2} e^{- 3 t} + t

Solution steps

3 y^{''} (t) + 8 y^{'} (t) - 3 y = 8 - 3 t

Solve linear ODE:

y = c_{1} e^{\frac{t}{3}} + c_{2} e^{- 3 t} + t

y = c_{1} e^{\frac{t}{3}} + c_{2} e^{- 3 t} + t

What is the solution for 3y^{''}+8y^'-3y=8-3t ?
The solution for 3y^{''}+8y^'-3y=8-3t is y=c_{1}e^{t/3}+c_{2}e^{-3t}+t