What is the solution for y^{''}+5y^'+6y=e^{2x} ?

The solution for y^{''}+5y^'+6y=e^{2x} is y=c_{1}e^{-2x}+c_{2}e^{-3x}+1/20 e^{2x}

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y^{''}+5y^'+6y=e^{2x}

y^{^{''}} + 5 y^{^{'}} + 6 y = e^{2 x}

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{1}{20} e^{2 x}

Solution steps

y^{''} (x) + 5 y^{'} (x) + 6 y = e^{2 x}

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{1}{20} e^{2 x}

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{1}{20} e^{2 x}

What is the solution for y^{''}+5y^'+6y=e^{2x} ?
The solution for y^{''}+5y^'+6y=e^{2x} is y=c_{1}e^{-2x}+c_{2}e^{-3x}+1/20 e^{2x}