What is the solution for u^{''}-a*\H(x)=x,u^'(-1)=0,u^'(1)=0 ?

The solution for u^{''}-a*\H(x)=x,u^'(-1)=0,u^'(1)=0 is u(x)=integral of integral of x+a\H(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

u^{''}-a*\H(x)=x,u^'(-1)=0,u^'(1)=0

u^{^{''}} - a \cdot H (x) = x, u^{^{'}} (- 1) = 0, u^{^{'}} (1) = 0

u (x) = \int \int x + a H (x) d x d x

Solution steps

u^{''} (x) - a \cdot H (x) = x

Isolate

u^{''} (x) : u^{''} (x) = x + a H (x)

Solve

u^{''} (x) = x + a H (x) : u^{'} (x) = \int x + a H (x) d x

Solve

u^{'} (x) = \int x + a H (x) d x : u (x) = \int \int x + a H (x) d x d x

u (x) = \int \int x + a H (x) d x d x

What is the solution for u^{''}-a*\H(x)=x,u^'(-1)=0,u^'(1)=0 ?
The solution for u^{''}-a*\H(x)=x,u^'(-1)=0,u^'(1)=0 is u(x)=integral of integral of x+a\H(x)