What is the solution for 2y^{''}+3y^'=-1 ?

The solution for 2y^{''}+3y^'=-1 is y=c_{1}+c_{2}e^{-(3t)/2}-t/3

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2y^{''}+3y^'=-1

2 y^{^{''}} + 3 y^{^{'}} = - 1

y = c_{1} + c_{2} e^{- \frac{3 t}{2}} - \frac{t}{3}

Solution steps

2 y^{''} (t) + 3 y^{'} (t) = - 1

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{3 t}{2}} - \frac{t}{3}

y = c_{1} + c_{2} e^{- \frac{3 t}{2}} - \frac{t}{3}

What is the solution for 2y^{''}+3y^'=-1 ?
The solution for 2y^{''}+3y^'=-1 is y=c_{1}+c_{2}e^{-(3t)/2}-t/3