y^{''}-4y^'+3=0

Lösung

y^{^{''}} - 4 y^{^{'}} + 3 = 0

y = c_{1} e^{4 t} + c_{2} + \frac{3 t}{4}

Schritte zur Lösung

y^{''} (t) - 4 y^{'} (t) + 3 = 0

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} + \frac{3 t}{4}

y = c_{1} e^{4 t} + c_{2} + \frac{3 t}{4}

y^{^{''}} + 3 y = 6 x

y^{^{''}} - 3 y^{^{'}} + 2 = 0

- 2 y^{^{''}} + 7 y^{^{'}} - y - 8 = - 6 x^{2} - 2 x^{3} e^{x}

y^{^{''}} - y^{^{'}} - 2 y = 4 t^{2}

\frac{d ^{2} y}{d x ^{2}} + 25 y = 5 x^{2} + x