y^{''}+3y^'=sin(3x)

Lösung

y^{^{''}} + 3 y^{^{'}} = sin (3 x)

y = c_{1} + c_{2} e^{- 3 x} - \frac{1}{18} sin (3 x) - \frac{1}{18} cos (3 x)

Schritte zur Lösung

y^{''} (x) + 3 y^{'} (x) = sin (3 x)

Solve linear ODE:

y = c_{1} + c_{2} e^{- 3 x} - \frac{1}{18} sin (3 x) - \frac{1}{18} cos (3 x)

y = c_{1} + c_{2} e^{- 3 x} - \frac{1}{18} sin (3 x) - \frac{1}{18} cos (3 x)

y^{^{''}} + 16 y = 5 sin (x)

y^{^{''}} - y = 1, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} + y^{^{'}} - 6 y = 36 t

y^{^{''}} + y^{^{'}} - 2 y = x \cdot e^{x}

y^{^{''}} - y = sec (x)