Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}+y=cos(x)+sec(x)y^{''}-5y^'+6y=2e^{-x}y^{''}-2y^'+y=13e^xy^{''}-y^'=e^x+1y^{''}-5y^'+6y=2te^{2t},y^'(0)=-3
Frequently Asked Questions (FAQ)
What is the solution for y^{''}+2y^'+y=t ?
The solution for y^{''}+2y^'+y=t is y=c_{1}e^{-t}+c_{2}te^{-t}+t-2