What is the solution for y^{''}+4y^'+3y-3x=0 ?

The solution for y^{''}+4y^'+3y-3x=0 is y=c_{1}e^{-x}+c_{2}e^{-3x}+x-4/3

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y^{''}+4y^'+3y-3x=0

y^{^{''}} + 4 y^{^{'}} + 3 y - 3 x = 0

y = c_{1} e^{- x} + c_{2} e^{- 3 x} + x - \frac{4}{3}

Solution steps

y^{''} (x) + 4 y^{'} (x) + 3 y - 3 x = 0

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} e^{- 3 x} + x - \frac{4}{3}

y = c_{1} e^{- x} + c_{2} e^{- 3 x} + x - \frac{4}{3}

What is the solution for y^{''}+4y^'+3y-3x=0 ?
The solution for y^{''}+4y^'+3y-3x=0 is y=c_{1}e^{-x}+c_{2}e^{-3x}+x-4/3