What is the solution for y^{''}+16y=sec(4) ?

The solution for y^{''}+16y=sec(4) is y=c_{1}cos(4t)+c_{2}sin(4t)+(sec(4))/(16)

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y^{''}+16y=sec(4)

y^{^{''}} + 16 y = sec (4)

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{sec ( 4 )}{16}

Solution steps

y^{''} (t) + 16 y = sec (4)

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{sec ( 4 )}{16}

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{sec ( 4 )}{16}

What is the solution for y^{''}+16y=sec(4) ?
The solution for y^{''}+16y=sec(4) is y=c_{1}cos(4t)+c_{2}sin(4t)+(sec(4))/(16)