What is the solution for (D^4+D^2)y=18x-4sin(x) ?

The solution for (D^4+D^2)y=18x-4sin(x) is y=c_{1}+c_{2}x+c_{3}cos(x)+c_{4}sin(x)+3x^3-2xcos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(D^4+D^2)y=18x-4sin(x)

(D^{4} + D^{2}) y = 18 x - 4 sin (x)

y = c_{1} + c_{2} x + c_{3} cos (x) + c_{4} sin (x) + 3 x^{3} - 2 x cos (x)

Solution steps

(D^{4} + D^{2}) y = 18 x - 4 sin (x)

Solve linear ODE:

y = c_{1} + c_{2} x + c_{3} cos (x) + c_{4} sin (x) + 3 x^{3} - 2 x cos (x)

y = c_{1} + c_{2} x + c_{3} cos (x) + c_{4} sin (x) + 3 x^{3} - 2 x cos (x)

What is the solution for (D^4+D^2)y=18x-4sin(x) ?
The solution for (D^4+D^2)y=18x-4sin(x) is y=c_{1}+c_{2}x+c_{3}cos(x)+c_{4}sin(x)+3x^3-2xcos(x)