What is the solution for 9y^{''}-4y=sin(x) ?

The solution for 9y^{''}-4y=sin(x) is y=c_{1}e^{(2x)/3}+c_{2}e^{-(2x)/3}-1/13 sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

9y^{''}-4y=sin(x)

9 y^{^{''}} - 4 y = sin (x)

y = c_{1} e^{\frac{2 x}{3}} + c_{2} e^{- \frac{2 x}{3}} - \frac{1}{13} sin (x)

Solution steps

9 y^{''} (x) - 4 y = sin (x)

Solve linear ODE:

y = c_{1} e^{\frac{2 x}{3}} + c_{2} e^{- \frac{2 x}{3}} - \frac{1}{13} sin (x)

y = c_{1} e^{\frac{2 x}{3}} + c_{2} e^{- \frac{2 x}{3}} - \frac{1}{13} sin (x)

What is the solution for 9y^{''}-4y=sin(x) ?
The solution for 9y^{''}-4y=sin(x) is y=c_{1}e^{(2x)/3}+c_{2}e^{-(2x)/3}-1/13 sin(x)