What is the solution for y^{''}+y=3xsin(x) ?

The solution for y^{''}+y=3xsin(x) is y=c_{1}cos(x)+c_{2}sin(x)-(3x^2cos(x))/4+(3xsin(x))/4

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y^{''}+y=3xsin(x)

y^{^{''}} + y = 3 x sin (x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x ^{2} cos ( x )}{4} + \frac{3 x sin ( x )}{4}

Solution steps

y^{''} (x) + y = 3 x sin (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x ^{2} cos ( x )}{4} + \frac{3 x sin ( x )}{4}

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x ^{2} cos ( x )}{4} + \frac{3 x sin ( x )}{4}

What is the solution for y^{''}+y=3xsin(x) ?
The solution for y^{''}+y=3xsin(x) is y=c_{1}cos(x)+c_{2}sin(x)-(3x^2cos(x))/4+(3xsin(x))/4