What is the solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 ?

The solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 is y=sqrt(18x+c_{1)},y=-sqrt(18x+c_{1)}

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(dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1

\frac{d y}{d x} = \frac{2 ^{3} + 1}{y}, y = 2, x = 2 y, x = 1

y = 18 x + c_{1}, y = - 18 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{2 ^{3} + 1}{y}

Solve separable ODE:

y = 18 x + c_{1}, y = - 18 x + c_{1}

y = 18 x + c_{1}, y = - 18 x + c_{1}

What is the solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 ?
The solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 is y=sqrt(18x+c_{1)},y=-sqrt(18x+c_{1)}