What is the solution for (dy)/(dx)=(x^2+1)/(xy) ?

The solution for (dy)/(dx)=(x^2+1)/(xy) is y=sqrt(x^2+2ln(x)+c_{1)},y=-sqrt(x^2+2ln(x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dx)=(x^2+1)/(xy)

\frac{d y}{d x} = \frac{x ^{2} + 1}{x y}

y = x^{2} + 2 ln (x) + c_{1}, y = - x^{2} + 2 ln (x) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} + 1}{x y}

Solve separable ODE:

y = x^{2} + 2 ln (x) + c_{1}, y = - x^{2} + 2 ln (x) + c_{1}

y = x^{2} + 2 ln (x) + c_{1}, y = - x^{2} + 2 ln (x) + c_{1}

What is the solution for (dy)/(dx)=(x^2+1)/(xy) ?
The solution for (dy)/(dx)=(x^2+1)/(xy) is y=sqrt(x^2+2ln(x)+c_{1)},y=-sqrt(x^2+2ln(x)+c_{1)}