What is the solution for h'+(0.18h^{(-3)/2}) 1/pi =0 ?

The solution for h'+(0.18h^{(-3)/2}) 1/pi =0 is h(t)=(-0.14323…t-c_{1})^{2/5}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

h'+(0.18h^{(-3)/2}) 1/pi =0

h^{^{'}} + (0.18 h^{\frac{- 3}{2}}) \frac{1}{π} = 0

h (t) = (- 0.14323 \dots t - c_{1})^{\frac{2}{5}}

Solution steps

h^{'} (t) + (0.18 h (t)^{\frac{- 3}{2}}) \frac{1}{π} = 0

Solve separable ODE:

h (t) = (- 0.14323 \dots t - c_{1})^{\frac{2}{5}}

h (t) = (- 0.14323 \dots t - c_{1})^{\frac{2}{5}}

What is the solution for h'+(0.18h^{(-3)/2}) 1/pi =0 ?
The solution for h'+(0.18h^{(-3)/2}) 1/pi =0 is h(t)=(-0.14323…t-c_{1})^{2/5}