What is the solution for derivative of 6x^2+7y^2-1=0 ?

The solution for derivative of 6x^2+7y^2-1=0 is y=sqrt((c_{1)-6x^2+1)/7},y=-sqrt((c_{1)-6x^2+1)/7}

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derivative of 6x^2+7y^2-1=0

\frac{d}{d x} (6 x^{2} + 7 y^{2} - 1) = 0

y = \frac{c _{1} - 6 x ^{2} + 1}{7}, y = - \frac{c _{1} - 6 x ^{2} + 1}{7}

Solution steps

\frac{d}{d x} (6 x^{2} + 7 y^{2} - 1) = 0

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

6 x^{2} + 7 y^{2} - 1 = \int 0 d x

\int 0 d x = c_{1}

6 x^{2} + 7 y^{2} - 1 = c_{1}

Isolate

y : y = \frac{c _{1} - 6 x ^{2} + 1}{7}, y = - \frac{c _{1} - 6 x ^{2} + 1}{7}

y = \frac{c _{1} - 6 x ^{2} + 1}{7}, y = - \frac{c _{1} - 6 x ^{2} + 1}{7}

What is the solution for derivative of 6x^2+7y^2-1=0 ?
The solution for derivative of 6x^2+7y^2-1=0 is y=sqrt((c_{1)-6x^2+1)/7},y=-sqrt((c_{1)-6x^2+1)/7}