What is the solution for (dy)/(dx)y-6x^3+cos(x)=0 ?

The solution for (dy)/(dx)y-6x^3+cos(x)=0 is y=sqrt(3x^4-2sin(x)+c_{1)},y=-sqrt(3x^4-2sin(x)+c_{1)}

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(dy)/(dx)y-6x^3+cos(x)=0

\frac{d y}{d x} y - 6 x^{3} + cos (x) = 0

y = 3 x^{4} - 2 sin (x) + c_{1}, y = - 3 x^{4} - 2 sin (x) + c_{1}

Solution steps

\frac{d y}{d x} y - 6 x^{3} + cos (x) = 0

Solve separable ODE:

y = 3 x^{4} - 2 sin (x) + c_{1}, y = - 3 x^{4} - 2 sin (x) + c_{1}

y = 3 x^{4} - 2 sin (x) + c_{1}, y = - 3 x^{4} - 2 sin (x) + c_{1}

What is the solution for (dy)/(dx)y-6x^3+cos(x)=0 ?
The solution for (dy)/(dx)y-6x^3+cos(x)=0 is y=sqrt(3x^4-2sin(x)+c_{1)},y=-sqrt(3x^4-2sin(x)+c_{1)}