What is the solution for y^'(s)(-s^2-2s)-2sy(s)=0 ?

The solution for y^'(s)(-s^2-2s)-2sy(s)=0 is y(s)=(c_{1})/(s^2+4s+4)

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y^'(s)(-s^2-2s)-2sy(s)=0

y^{^{'}} (s) (- s^{2} - 2 s) - 2 sy (s) = 0

y (s) = \frac{c _{1}}{s ^{2} + 4 s + 4}

Solution steps

y^{'} (s) (- s^{2} - 2 s) - 2 sy (s) = 0

Solve separable ODE:

y (s) = \frac{c _{1}}{s ^{2} + 4 s + 4}

y (s) = \frac{c _{1}}{s ^{2} + 4 s + 4}

What is the solution for y^'(s)(-s^2-2s)-2sy(s)=0 ?
The solution for y^'(s)(-s^2-2s)-2sy(s)=0 is y(s)=(c_{1})/(s^2+4s+4)