(t^2+1)x^'=-3tx+6t

Lösung

(t^{2} + 1) x^{^{'}} = - 3 t x + 6 t

x = \frac{c _{1}}{( t ^{2} + 1 ) ^{\frac{3}{2}}} + 2

Schritte zur Lösung

(t^{2} + 1) x^{'} (t) = - 3 t x + 6 t

Solve separable ODE:

x = \frac{c _{1}}{( t ^{2} + 1 ) ^{\frac{3}{2}}} + 2

x = \frac{c _{1}}{( t ^{2} + 1 ) ^{\frac{3}{2}}} + 2