What is the solution for (dy)/(dt)= t/(t^2y-y) ?

The solution for (dy)/(dt)= t/(t^2y-y) is y=sqrt(ln(t^2-1)+c_{1)},y=-sqrt(ln(t^2-1)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dt)= t/(t^2y-y)

\frac{d y}{d t} = \frac{t}{t ^{2} y - y}

y = ln (t^{2} - 1) + c_{1}, y = - ln (t^{2} - 1) + c_{1}

Solution steps

\frac{d y}{d t} = \frac{t}{t ^{2} y - y}

Solve separable ODE:

y = ln (t^{2} - 1) + c_{1}, y = - ln (t^{2} - 1) + c_{1}

y = ln (t^{2} - 1) + c_{1}, y = - ln (t^{2} - 1) + c_{1}

What is the solution for (dy)/(dt)= t/(t^2y-y) ?
The solution for (dy)/(dt)= t/(t^2y-y) is y=sqrt(ln(t^2-1)+c_{1)},y=-sqrt(ln(t^2-1)+c_{1)}