What is the solution for y^'=((3x^2))/((4+2y)) ?

The solution for y^'=((3x^2))/((4+2y)) is y=-2+sqrt(x^3+c_{1)+4},y=-sqrt(x^3+c_{1)+4}-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=((3x^2))/((4+2y))

y^{^{'}} = \frac{( 3 x ^{2} )}{( 4 + 2 y )}

y = - 2 + x^{3} + c_{1} + 4, y = - x^{3} + c_{1} + 4 - 2

Solution steps

y^{'} (x) = \frac{( 3 x ^{2} )}{( 4 + 2 y )}

Solve separable ODE:

y = - 2 + x^{3} + c_{1} + 4, y = - x^{3} + c_{1} + 4 - 2

y = - 2 + x^{3} + c_{1} + 4, y = - x^{3} + c_{1} + 4 - 2

What is the solution for y^'=((3x^2))/((4+2y)) ?
The solution for y^'=((3x^2))/((4+2y)) is y=-2+sqrt(x^3+c_{1)+4},y=-sqrt(x^3+c_{1)+4}-2