What is the (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 ?

The (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 is x^3

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(dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1

\frac{d y}{d x} = \frac{x ^{3}}{( y + 2 ) ^{2}}, y (0) = - 1

x^{3}

Solution steps

\frac{x ^{3}}{( y + 2 ) ^{2}} = \frac{x ^{3}}{( y + 2 ) ^{2}}

Constant function results in a constant

y (0) = - 1

= \frac{x ^{3}}{( - 1 + 2 ) ^{2}}

Expand

\frac{x ^{3}}{( - 1 + 2 ) ^{2}} : x^{3}

= x^{3}

What is the (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 ?
The (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 is x^3