What is the derivative of 4x^2+3x+2 ?

The derivative of 4x^2+3x+2 is 8x+3

What is the first derivative of 4x^2+3x+2 ?

The first derivative of 4x^2+3x+2 is 8x+3

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\frac{d}{d x} (4 x^{2} + 3 x + 2)

8 x + 3

Solution steps

\frac{d}{d x} (4 x^{2} + 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 8 x + 3 + 0

Simplify

= 8 x + 3

d er i v a t i v e y = e^{e}

\int x^{2} (1 - x) d x

\int \frac{sin ( x )}{x} d x

\int_{0}^{1} \frac{1}{( 2 x - 3 ) ^{2}} d x

\frac{d}{d x} (\frac{192}{x ^{4}})

What is the derivative of 4x^2+3x+2 ?
The derivative of 4x^2+3x+2 is 8x+3
What is the first derivative of 4x^2+3x+2 ?
The first derivative of 4x^2+3x+2 is 8x+3