What is the solution for y^'=e^{(2+3)x+(1+1)y} ?

The solution for y^'=e^{(2+3)x+(1+1)y} is y=-(ln(-2/5 e^{5x}-c_{1}))/2

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y^'=e^{(2+3)x+(1+1)y}

y^{^{'}} = e^{(2 + 3) x + (1 + 1) y}

y = - \frac{ln ( - \frac{2}{5} e ^{5 x} - c _{1} )}{2}

Solution steps

y^{'} (x) = e^{(2 + 3) x + (1 + 1) y}

Solve separable ODE:

y = - \frac{ln ( - \frac{2}{5} e ^{5 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{5} e ^{5 x} - c _{1} )}{2}

What is the solution for y^'=e^{(2+3)x+(1+1)y} ?
The solution for y^'=e^{(2+3)x+(1+1)y} is y=-(ln(-2/5 e^{5x}-c_{1}))/2