What is the solution for (2dy)/(dt)+4y=6,y(0)=1(1/2) ?

The solution for (2dy)/(dt)+4y=6,y(0)=1(1/2) is y=-(e^{-2t-c_{1}})/2+3/2

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(2dy)/(dt)+4y=6,y(0)=1(1/2)

\frac{2 d y}{d t} + 4 y = 6, y (0) = 1 (\frac{1}{2})

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{3}{2}

Solution steps

\frac{2 d y}{d t} + 4 y = 6

Solve separable ODE:

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{3}{2}

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{3}{2}

What is the solution for (2dy)/(dt)+4y=6,y(0)=1(1/2) ?
The solution for (2dy)/(dt)+4y=6,y(0)=1(1/2) is y=-(e^{-2t-c_{1}})/2+3/2