What is the solution for y^'-sin(y)=1 ?

The solution for y^'-sin(y)=1 is y=2arctan((-2-t-c_{1})/(t+c_{1)})+2pin

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y^'-sin(y)=1

y^{^{'}} - sin (y) = 1

y = 2 arctan (\frac{- 2 - t - c _{1}}{t + c _{1}}) + 2 πn

Solution steps

y^{'} (t) - sin (y) = 1

Solve separable ODE:

y = 2 arctan (\frac{- 2 - t - c _{1}}{t + c _{1}}) + 2 πn

y = 2 arctan (\frac{- 2 - t - c _{1}}{t + c _{1}}) + 2 πn

What is the solution for y^'-sin(y)=1 ?
The solution for y^'-sin(y)=1 is y=2arctan((-2-t-c_{1})/(t+c_{1)})+2pin