What is the solution for (dy)/(dt)+sqrt(1+t^2)y=0 ?

The solution for (dy)/(dt)+sqrt(1+t^2)y=0 is y=sqrt(-e^{-t\sqrt{1+t^2)+c_{1}}(t-sqrt(1+t^2))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dt)+sqrt(1+t^2)y=0

\frac{d y}{d t} + 1 + t^{2} y = 0

y = - e^{- t 1 + t^{2} + c_{1}} (t - 1 + t^{2})

Solution steps

\frac{d y}{d t} + 1 + t^{2} y = 0

Solve separable ODE:

y = - e^{- t 1 + t^{2} + c_{1}} (t - 1 + t^{2})

y = - e^{- t 1 + t^{2} + c_{1}} (t - 1 + t^{2})

What is the solution for (dy)/(dt)+sqrt(1+t^2)y=0 ?
The solution for (dy)/(dt)+sqrt(1+t^2)y=0 is y=sqrt(-e^{-t\sqrt{1+t^2)+c_{1}}(t-sqrt(1+t^2))}