What is the solution for xy(y+2)dx-(y+1)dy=0 ?

The solution for xy(y+2)dx-(y+1)dy=0 is y=-1+sqrt(e^{x^2+c_{1)}+1},y=-sqrt(e^{x^2+c_{1)}+1}-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

xy(y+2)dx-(y+1)dy=0

x y (y + 2) d x - (y + 1) d y = 0

y = - 1 + e^{x^{2} + c_{1}} + 1, y = - e^{x^{2} + c_{1}} + 1 - 1

Solution steps

x y (y + 2) d x - (y + 1) d y = 0

Solve separable ODE:

y = - 1 + e^{x^{2} + c_{1}} + 1, y = - e^{x^{2} + c_{1}} + 1 - 1

y = - 1 + e^{x^{2} + c_{1}} + 1, y = - e^{x^{2} + c_{1}} + 1 - 1

What is the solution for xy(y+2)dx-(y+1)dy=0 ?
The solution for xy(y+2)dx-(y+1)dy=0 is y=-1+sqrt(e^{x^2+c_{1)}+1},y=-sqrt(e^{x^2+c_{1)}+1}-1