What is the solution for (dy)/(dt)=2tcos^2(y),y(0)= pi/4 ?

The solution for (dy)/(dt)=2tcos^2(y),y(0)= pi/4 is y=arctan(t^2+1)+pin

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(dy)/(dt)=2tcos^2(y),y(0)= pi/4

\frac{d y}{d t} = 2 t cos^{2} (y), y (0) = \frac{π}{4}

y = arctan (t^{2} + 1) + πn

Solution steps

\frac{d y}{d t} = 2 t cos^{2} (y)

Solve separable ODE:

y = arctan (t^{2} + 1) + πn

y = arctan (t^{2} + 1) + πn

What is the solution for (dy)/(dt)=2tcos^2(y),y(0)= pi/4 ?
The solution for (dy)/(dt)=2tcos^2(y),y(0)= pi/4 is y=arctan(t^2+1)+pin