What is the solution for 220=(0.5)(x)+(15.5)(dx)/(dt)+(20) ?

The solution for 220=(0.5)(x)+(15.5)(dx)/(dt)+(20) is x=2e^{(-t-c_{1})/(31)}+400

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

220=(0.5)(x)+(15.5)(dx)/(dt)+(20)

220 = (0.5) (x) + (15.5) \frac{d x}{d t} + (20)

x = 2 e^{\frac{- t - c _{1}}{31}} + 400

Solution steps

220 = (0.5) (x) + (15.5) \frac{d x}{d t} + (20)

Solve separable ODE:

x = 2 e^{\frac{- t - c _{1}}{31}} + 400

x = 2 e^{\frac{- t - c _{1}}{31}} + 400

What is the solution for 220=(0.5)(x)+(15.5)(dx)/(dt)+(20) ?
The solution for 220=(0.5)(x)+(15.5)(dx)/(dt)+(20) is x=2e^{(-t-c_{1})/(31)}+400