What is the solution for x(dy)/(dx)=1-x^2+y^2-x^2y^2 ?

The solution for x(dy)/(dx)=1-x^2+y^2-x^2y^2 is y=tan(-(x^2)/2+ln(x)+c_{1})

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x(dy)/(dx)=1-x^2+y^2-x^2y^2

x \frac{d y}{d x} = 1 - x^{2} + y^{2} - x^{2} y^{2}

y = tan (- \frac{x ^{2}}{2} + ln (x) + c_{1})

Solution steps

x \frac{d y}{d x} = 1 - x^{2} + y^{2} - x^{2} y^{2}

Solve separable ODE:

y = tan (- \frac{x ^{2}}{2} + ln (x) + c_{1})

y = tan (- \frac{x ^{2}}{2} + ln (x) + c_{1})

What is the solution for x(dy)/(dx)=1-x^2+y^2-x^2y^2 ?
The solution for x(dy)/(dx)=1-x^2+y^2-x^2y^2 is y=tan(-(x^2)/2+ln(x)+c_{1})