What is the solution for xy^'=(3y^3+12yx^2)/(2y^2+8x^2) ?

The solution for xy^'=(3y^3+12yx^2)/(2y^2+8x^2) is y=c_{1}x^{3/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

xy^'=(3y^3+12yx^2)/(2y^2+8x^2)

x y^{^{'}} = \frac{3 y ^{3} + 12 y x ^{2}}{2 y ^{2} + 8 x ^{2}}

y = c_{1} x^{\frac{3}{2}}

Solution steps

x y^{'} (x) = \frac{3 y ^{3} + 12 y x ^{2}}{2 y ^{2} + 8 x ^{2}}

Solve separable ODE:

y = c_{1} x^{\frac{3}{2}}

y = c_{1} x^{\frac{3}{2}}

What is the solution for xy^'=(3y^3+12yx^2)/(2y^2+8x^2) ?
The solution for xy^'=(3y^3+12yx^2)/(2y^2+8x^2) is y=c_{1}x^{3/2}