What is the solution for (dy)/(dt)=(3t^2+4t+2)/(2y-2),y(0)=-1 ?

The solution for (dy)/(dt)=(3t^2+4t+2)/(2y-2),y(0)=-1 is y=1-sqrt((t^2+2)(t+2))

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(dy)/(dt)=(3t^2+4t+2)/(2y-2),y(0)=-1

\frac{d y}{d t} = \frac{3 t ^{2} + 4 t + 2}{2 y - 2}, y (0) = - 1

y = 1 - (t^{2} + 2) (t + 2)

Solution steps

\frac{d y}{d t} = \frac{3 t ^{2} + 4 t + 2}{2 y - 2}

Solve separable ODE:

y = 1 - (t^{2} + 2) (t + 2)

y = 1 - (t^{2} + 2) (t + 2)

What is the solution for (dy)/(dt)=(3t^2+4t+2)/(2y-2),y(0)=-1 ?
The solution for (dy)/(dt)=(3t^2+4t+2)/(2y-2),y(0)=-1 is y=1-sqrt((t^2+2)(t+2))