What is the solution for (dy)/(dx)=e^{2x-y},y(0)=0 ?

The solution for (dy)/(dx)=e^{2x-y},y(0)=0 is y=ln(1/2 e^{2x}+1/2)

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(dy)/(dx)=e^{2x-y},y(0)=0

\frac{d y}{d x} = e^{2 x - y}, y (0) = 0

y = ln (\frac{1}{2} e^{2 x} + \frac{1}{2})

Solution steps

\frac{d y}{d x} = e^{2 x - y}

Solve separable ODE:

y = ln (\frac{1}{2} e^{2 x} + \frac{1}{2})

y = ln (\frac{1}{2} e^{2 x} + \frac{1}{2})

What is the solution for (dy)/(dx)=e^{2x-y},y(0)=0 ?
The solution for (dy)/(dx)=e^{2x-y},y(0)=0 is y=ln(1/2 e^{2x}+1/2)