What is the solution for (dy)/(dt)=2ty^2+3t^2y^2 ?

The solution for (dy)/(dt)=2ty^2+3t^2y^2 is y=-1/(t^3+t^2+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dt)=2ty^2+3t^2y^2

\frac{d y}{d t} = 2 t y^{2} + 3 t^{2} y^{2}

y = - \frac{1}{t ^{3} + t ^{2} + c _{1}}

Solution steps

\frac{d y}{d t} = 2 t y^{2} + 3 t^{2} y^{2}

Solve separable ODE:

y = - \frac{1}{t ^{3} + t ^{2} + c _{1}}

y = - \frac{1}{t ^{3} + t ^{2} + c _{1}}

What is the solution for (dy)/(dt)=2ty^2+3t^2y^2 ?
The solution for (dy)/(dt)=2ty^2+3t^2y^2 is y=-1/(t^3+t^2+c_{1)}