What is the solution for (dy)/(dx)=(1-y^2) ?

The solution for (dy)/(dx)=(1-y^2) is y=-(e^{2x+2c_{1}})/(1-e^{2(x+c_{1))}}-1/(1-e^{2(x+c_{1))}}

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(dy)/(dx)=(1-y^2)

\frac{d y}{d x} = (1 - y^{2})

y = - \frac{e ^{2 x + 2 c_{1}}}{1 - e ^{2 (x + c_{1})}} - \frac{1}{1 - e ^{2 (x + c_{1})}}

Solution steps

\frac{d y}{d x} = (1 - y^{2})

Solve separable ODE:

y = - \frac{e ^{2 x + 2 c_{1}}}{1 - e ^{2 (x + c_{1})}} - \frac{1}{1 - e ^{2 (x + c_{1})}}

y = - \frac{e ^{2 x + 2 c_{1}}}{1 - e ^{2 (x + c_{1})}} - \frac{1}{1 - e ^{2 (x + c_{1})}}

What is the solution for (dy)/(dx)=(1-y^2) ?
The solution for (dy)/(dx)=(1-y^2) is y=-(e^{2x+2c_{1}})/(1-e^{2(x+c_{1))}}-1/(1-e^{2(x+c_{1))}}