What is the solution for xy^'+8y+7=7x^2y^'+7y ?

The solution for xy^'+8y+7=7x^2y^'+7y is y=e^{-c_{1}}-(e^{-c_{1}})/(7x)-7

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xy^'+8y+7=7x^2y^'+7y

x y^{^{'}} + 8 y + 7 = 7 x^{2} y^{^{'}} + 7 y

y = e^{- c_{1}} - \frac{e ^{- c_{1}}}{7 x} - 7

Solution steps

x y^{'} (x) + 8 y + 7 = 7 x^{2} y^{'} (x) + 7 y

Solve separable ODE:

y = e^{- c_{1}} - \frac{e ^{- c_{1}}}{7 x} - 7

y = e^{- c_{1}} - \frac{e ^{- c_{1}}}{7 x} - 7

What is the solution for xy^'+8y+7=7x^2y^'+7y ?
The solution for xy^'+8y+7=7x^2y^'+7y is y=e^{-c_{1}}-(e^{-c_{1}})/(7x)-7