What is the solution for (dy)/(dx)=(sqrt(y))/(2x+1),y(0)=4 ?

The solution for (dy)/(dx)=(sqrt(y))/(2x+1),y(0)=4 is y=(ln^2(2x+1))/(16)+ln(2x+1)+4

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(dy)/(dx)=(sqrt(y))/(2x+1),y(0)=4

\frac{d y}{d x} = \frac{y}{2 x + 1}, y (0) = 4

y = \frac{ln ^{2} ( 2 x + 1 )}{16} + ln (2 x + 1) + 4

Solution steps

\frac{d y}{d x} = \frac{y}{2 x + 1}

Solve separable ODE:

y = \frac{ln ^{2} ( 2 x + 1 )}{16} + ln (2 x + 1) + 4

y = \frac{ln ^{2} ( 2 x + 1 )}{16} + ln (2 x + 1) + 4

What is the solution for (dy)/(dx)=(sqrt(y))/(2x+1),y(0)=4 ?
The solution for (dy)/(dx)=(sqrt(y))/(2x+1),y(0)=4 is y=(ln^2(2x+1))/(16)+ln(2x+1)+4