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Popular Calculus >

y^'(t)=(1-y)(3+y),y(0)=3

Solution

y^{^{'}} (t) = (1 - y) (3 + y), y (0) = 3

Solution

3 - 2 y - y^{2}

Solution steps

Find

(1 - y) (3 + y)

given

y (0) = 3

(1 - y) (3 + y) = (1 - y) (3 + y)

y : 3

y : 3

= (1 - y) (3 + y)

Expand

(1 - y) (3 + y) : 3 - 2 y - y^{2}

= 3 - 2 y - y^{2}

Graph

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Frequently Asked Questions (FAQ)

What is the y^'(t)=(1-y)(3+y),y(0)=3 ?
The y^'(t)=(1-y)(3+y),y(0)=3 is 3-2y-y^2