What is the solution for y^'=b-b*y-a*y ?

The solution for y^'=b-b*y-a*y is y=-(e^{-bt-at-c_{1}b-c_{1}a})/(b+a)+b/(b+a)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=b-by-ay

y^{^{'}} = b - b \cdot y - a \cdot y

y = - \frac{e ^{- b t - a t - c_{1} b - c_{1} a}}{b + a} + \frac{b}{b + a}

Solution steps

y^{'} (t) = b - b \cdot y - a \cdot y

Solve separable ODE:

y = - \frac{e ^{- b t - a t - c_{1} b - c_{1} a}}{b + a} + \frac{b}{b + a}

y = - \frac{e ^{- b t - a t - c_{1} b - c_{1} a}}{b + a} + \frac{b}{b + a}

What is the solution for y^'=b-b*y-a*y ?
The solution for y^'=b-b*y-a*y is y=-(e^{-bt-at-c_{1}b-c_{1}a})/(b+a)+b/(b+a)