What is the solution for (1-y^2)^{1/2}dx-(1-x^2)^{1/2}dy=0 ?

The solution for (1-y^2)^{1/2}dx-(1-x^2)^{1/2}dy=0 is y=sin(arcsin(x)+c_{1})

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(1-y^2)^{1/2}dx-(1-x^2)^{1/2}dy=0

(1 - y^{2})^{\frac{1}{2}} d x - (1 - x^{2})^{\frac{1}{2}} d y = 0

y = sin (arcsin (x) + c_{1})

Solution steps

(1 - y^{2})^{\frac{1}{2}} d x - (1 - x^{2})^{\frac{1}{2}} d y = 0

Solve separable ODE:

y = sin (arcsin (x) + c_{1})

y = sin (arcsin (x) + c_{1})

What is the solution for (1-y^2)^{1/2}dx-(1-x^2)^{1/2}dy=0 ?
The solution for (1-y^2)^{1/2}dx-(1-x^2)^{1/2}dy=0 is y=sin(arcsin(x)+c_{1})