What is the solution for y^'sec(x)=6y^2,y((9pi)/2)= 1/7 ?

The solution for y^'sec(x)=6y^2,y((9pi)/2)= 1/7 is y=-1/(6sin(x)-13)

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y^'sec(x)=6y^2,y((9pi)/2)= 1/7

y^{^{'}} sec (x) = 6 y^{2}, y (\frac{9 π}{2}) = \frac{1}{7}

y = - \frac{1}{6 sin ( x ) - 13}

Solution steps

y^{'} (x) sec (x) = 6 y^{2}

Solve separable ODE:

y = - \frac{1}{6 sin ( x ) - 13}

y = - \frac{1}{6 sin ( x ) - 13}

What is the solution for y^'sec(x)=6y^2,y((9pi)/2)= 1/7 ?
The solution for y^'sec(x)=6y^2,y((9pi)/2)= 1/7 is y=-1/(6sin(x)-13)