What is the solution for (dP)/(dt)=0.05P-0.00125P(t)^2 ?

The solution for (dP)/(dt)=0.05P-0.00125P(t)^2 is P=e^{0.05t-0.00041…t^3+c_{1}}

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(dP)/(dt)=0.05P-0.00125P(t)^2

\frac{d P}{d t} = 0.05 P - 0.00125 P^{2}

P = e^{0.05 t - 0.00041 \dots t^{3} + c_{1}}

Solution steps

\frac{d P}{d t} = 0.05 P - 0.00125 P t^{2}

Solve separable ODE:

P = e^{0.05 t - 0.00041 \dots t^{3} + c_{1}}

P = e^{0.05 t - 0.00041 \dots t^{3} + c_{1}}

What is the solution for (dP)/(dt)=0.05P-0.00125P(t)^2 ?
The solution for (dP)/(dt)=0.05P-0.00125P(t)^2 is P=e^{0.05t-0.00041…t^3+c_{1}}