What is the solution for xyy^'=(1+x^2) ?

The solution for xyy^'=(1+x^2) is y=sqrt(2ln(x)+x^2+c_{1)},y=-sqrt(2ln(x)+x^2+c_{1)}

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xyy^'=(1+x^2)

x y y^{^{'}} = (1 + x^{2})

y = 2 ln (x) + x^{2} + c_{1}, y = - 2 ln (x) + x^{2} + c_{1}

Solution steps

x y y^{'} (x) = (1 + x^{2})

Solve separable ODE:

y = 2 ln (x) + x^{2} + c_{1}, y = - 2 ln (x) + x^{2} + c_{1}

y = 2 ln (x) + x^{2} + c_{1}, y = - 2 ln (x) + x^{2} + c_{1}

What is the solution for xyy^'=(1+x^2) ?
The solution for xyy^'=(1+x^2) is y=sqrt(2ln(x)+x^2+c_{1)},y=-sqrt(2ln(x)+x^2+c_{1)}